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praksa
macek17 ::
PROBLEM: imam eno nalogo pri praksi
Izdelati moram program, s katerim bo možno preveriti, ali je vpisano število praštevilo ali ne. Kot namig, za preverjanje ali je vneseno število praštevilo, uporabite algoritem. Pokaziti mi mora vse praštavila(primer: vnesem številko 55 in mi mora od 1 do 55 izpisati vsa praštevila!)
Hvala
Izdelati moram program, s katerim bo možno preveriti, ali je vpisano število praštevilo ali ne. Kot namig, za preverjanje ali je vneseno število praštevilo, uporabite algoritem. Pokaziti mi mora vse praštavila(primer: vnesem številko 55 in mi mora od 1 do 55 izpisati vsa praštevila!)
Hvala
- premaknil iz Mali oglasi: OmegaBlue ()
whatever ::
Od vpisanega števila v zanki odštevaj 1 in hkrati preverjaj, če pri deljenju vpisanega števila s tem številom dobiš ostanek ali ne. Čim ne dobiš ostanka, število ni praštevilo (razen če si pri odštevanju že prišel do 1, potem je). Bolj optimizirana varianta pa je, da uporabiš nad vpisanim številom funkcijo sqrt, in nato odštevaš 1 od tega števila do 1.
Veliko jih je notri, še več jih je pa zunaj.
Bilijarde v šole! - Ivan Kramberger
Abnormal behaviour of abnormal brain makes me normal.
Bilijarde v šole! - Ivan Kramberger
Abnormal behaviour of abnormal brain makes me normal.
Tutankhamun ::
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AMD Phenom QUAD 9950 Black Edition, 8GB
Pimoz ::
lohka bi napisu vsaj v katerem jeziku....
tuki je primer v c++:
tuki je primer v c++:
#include <iostream> #include <cmath> using namespace std; int isItPrime (long long num) { if (num <= 1) return 0; if ((num == 2) || (num == 3)) return 1; long long module = num % 6; if (module == 1 || module == 5) { long long half = sqrt (num); for (long long i = 2; i <= half; i += (i == 2) ? 1 : 2) if (num % i == 0) { //cout << num << " " << i << endl; return 0; } } else return 0; return 1; } int main () { for (long long i = 0; i <= 2000000; i++) if (isItPrime (i) == 1) { cout << i << endl; sum += i; } return 0; }
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